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Cubic and Factorial Puzzle (Posted on 2015-06-23) Difficulty: 3 of 5
Find all triplets (X,Y,Z) of positive integers such that:
X3+ Y3+ Z3 = X! + Y! + Z! +11

No Solution Yet Submitted by K Sengupta    
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Solution computer solution Comment 1 of 1
(1, 2, 5) and its permutations

from

DefDbl A-Z
Dim crlf$



Private Sub Form_Load()
 Form1.Visible = True
 
 Text1.Text = ""
 crlf = Chr$(13) + Chr$(10)


 mn = 9999999999#
 For tot = 3 To 150
   For a = 1 To tot / 3
    a3 = a * a * a
    af = fact(a)
    For b = a To (tot - a) / 2
    b3 = b * b * b
    bf = fact(b)
      c = tot - a - b
      c3 = c * c * c
      cf = fact(c)
      diff = (a3 + b3 + c3) - (af + bf + cf)


      If Abs(diff) = 11 Then
       Text1.Text = Text1.Text & diff & "    " & a & Str(b) & Str(c) & crlf
      End If
    Next
   Next
 Next
 

 Text1.Text = Text1.Text & crlf & " done"
  
End Sub

Function fact(x)
  f = 1
  For i = 2 To x
    f = f * i
  Next
  fact = f
End Function


  Posted by Charlie on 2015-06-23 11:39:47
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