All about
flooble

fun stuff

Get a free chatterbox

Free JavaScript

Avatars
perplexus
dot
info
Home
>
Just Math
Simultaneous Pythagorean Poser (
Posted on 20150704
)
Find all possible triplets (A, B, C) of
positive integers
, with A ≤ B, that satisfy this system of equations:
A
^{2}
+ B
^{2}
= C
^{2}
, and:
A+B = C+12
No Solution Yet
Submitted by
K Sengupta
No Rating
Comments: (
Back to comment list
 You must be logged in to post comments.
)
solution
 Comment 1 of 4
Substitute C = (A+B)  12 into the first equation. The square terms conveniently cancel and the remaining terms can be factored as (A12)*(B12) = 72, giving solutions (A,B,C) = (84,13,85), (48,14,50), (36,15,39), (30,16,34), (24,18,30), (21,20,29).
Edited on
July 4, 2015, 11:54 am
Posted by
xdog
on 20150704 11:53:12
Please log in:
Login:
Password:
Remember me:
Sign up!

Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ

About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002  2020 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information