(In reply to Trigonometric solution
by Steve Herman)
Having sin(x)<cos(x) in itself doesn't show (sin(x))^(sin(x)) < (cos(x))^(cos(x)). It depends on some relationship between the sine function and the cosine function.
For example .1 < .5, but .1^.1 > .5^.5 (it's .7943282347242815 vs .7071067811865476).
Posted by Charlie
on 2015-02-12 08:57:31