All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Be consistent (Posted on 2015-02-20) Difficulty: 3 of 5
All integers (negative, zero and positive) are divided into 2 sets, male and female; none of those sets is an empty set.

Let:
male number + female number = male number
male number * female number = female number

Given the above, for each of the following equations specify whether the result Ri is a female number, a male number, or could be either:

R1= female number * female number
R2= female number + female number
R3 = male number * male number
R4= male number + male number

Please justify your decisions.

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts first thoughts | Comment 1 of 3
What first comes to mind is female numbers are even (including zero) and male numbers are odd (including 1). These being the additive and multiplicative identities, they result in fitting the description.

But female numbers could also be multiples of any consistently chosen k, say 4.  Male numbers would be those not divisible by 4.

Then two male numbers might add to either a male or a female number: 1 (male) + 1 (male) = 2 (male) but 2 (male) + 2 (male) = 4 (female). Two female numbers would add to another female number.

The same would apply to multiplication as one can see by using multiplication instead of addition in the examples shown in the paragraph above.


  Posted by Charlie on 2015-02-20 13:15:07
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (21)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information