All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Simultaneous Real Settlement (Posted on 2015-07-20)
Determine all quadruplets (P,Q,R,S) of real numbers that satisfy this system of equations:

(Q+R+S)2016 = 3P, and:

(P+R+S)2016 = 3Q, and:

(P+Q+S)2016 = 3R, and:

(P+Q+R)2016 = 3S

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 solution Comment 2 of 2 |
Look at the first equation.  LHS is never negative, so neither is RHS.  Similarly, Q, R, S are >=0 too.

Say you can order the unknowns P<Q<R<S.  Then substituting P for Q in first equation would make LHS<3P.  But the modified LHS=3Q by the second equation giving 3Q<3P, an impossibility.  By extension the same is true for the other unknowns.  Therefore they are all equal and the only solutions are the ones Jer noted:  P=0 and P=1/3.

 Posted by xdog on 2015-07-21 11:27:32

 Search: Search body:
Forums (1)