 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Smallest Perfect Cube Puzzle (Posted on 2015-07-15) Determine the smallest positive perfect cube whose first three digits (reading from the left) are 201 (in this order) and the last digit is 5.

 No Solution Yet Submitted by K Sengupta No Rating Comments: ( Back to comment list | You must be logged in to post comments.) simulation of manual trials Comment 2 of 2 | (In reply to computer assisted solution by Charlie)

ceil( 2010 ^(1/3))= 13
the cube of the next odd multiple of 5 is 3375

ceil( 20100 ^(1/3))= 28
the cube of the next odd multiple of 5 is 42875

ceil( 201000 ^(1/3))= 59
the cube of the next odd multiple of 5 is 274625

ceil( 2010000 ^(1/3))= 127
the cube of the next odd multiple of 5 is 2460375

ceil( 20100000 ^(1/3))= 272
the cube of the next odd multiple of 5 is 20796875

ceil( 201000000 ^(1/3))= 586
the cube of the next odd multiple of 5 is 210644875

ceil( 2010000000 ^(1/3))= 1263
the cube of the next odd multiple of 5 is 2024284625

ceil( 20100000000 ^(1/3))= 2719
the cube of the next odd multiple of 5 is 20234828125

ceil( 201000000000 ^(1/3))= 5858
the cube of the next odd multiple of 5 is 201745589625

 Posted by Charlie on 2015-07-15 16:19:57 Please log in:

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