All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Side Ratio Resolution (Posted on 2015-07-18) Difficulty: 3 of 5
Triangle PQR has incentre I and circumcentre O. Suppose that ∠ PIO = 90o and ∠ QIO = 45o.

Find the ratio PQ: QR : RP

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re: Solution | Comment 2 of 4 |
(In reply to Solution by Bractals)

I concur with your solution but you don't seem to indicate the 5:4:3 is the only ratio that works.  But from my sketch it is.

Some interesting things happened when I drew this on geometer's sketchpad:

I coordinatized and made I=(0,0), O=(1,0), P=(0,p), Q=(q,-q)
Constructing the circumcenter fixes Q (q is some function of p)
With line PQ known you can construct the incenter and the third corner of a triangle that has this incenter.  The point will only be on the circumcenter if P is in just the right spot.

It turns out (unproven) that P=(0,2), Q=(2,-2), R=(-6/5,-2/5)
PR = 6√5/5
RQ = 8√5/5
PQ = 10√5/5
So the ratio is 5:4:3



  Posted by Jer on 2015-07-20 10:04:08

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information