Find all real numbers A, B and C such that:

(A+1)*B*C =12, and:
(B+1)*A*C =4, and:
(C+1)*A*B =4

The 2nd and 3rd equation force B=C

SO

(A+1) * B^2=12

(B+1)*A*B=4

1st    A=2  B=C=-2

 2nd   A=1/3   B=C=3

Rem:  did not check for  other(if any) solutions

Posted by Ady TZIDON on 2015-08-09 01:30:51