19 is the only prime which is equal to the difference of two cubes of primes.
Prove the above statement.
p^3q^2=(pq)(p^2+pq+q^2)
The difference of cubes is only prime if one of the factors is 1.
p^2+pq+q^2 > 1 for any primes
pq=1 only for p=3, q=2 as they are the only primes that differ by 1.

Posted by Jer
on 20150331 11:59:48 