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Some sums (
Posted on 20150407
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Consider the two equalities:
1!+5! = 11^2
4!+5! = 12^2
Is there a pair of successive integers (below 1000) such that their squares can be written as a sum of 2 factorials?
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Submitted by
Ady TZIDON
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answer
 Comment 1 of 3
The answer is yes.
The pair given for consideration {11,12} is demonstrated by the assigned equalities to fulfill the requirement.
Besides the given pair {11, 12}, there is also the pair {12,11}.
(12)^2 = 144 = 4!+5!
(11)^2 = 121 = 1!+5! = 0!+5!
Posted by
Dej Mar
on 20150407 14:24:56
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