s(x) denotes the sum of digits of x.
Consider all the positive integer values of n satisfying s(n) = 100 arranged in strictly ascending order of magnitude.
Determine the 100th term of this sequence.
(In reply to
I've probably miscounted but here goes. by Charlie)
I got the same thing.
One thing that simplified some of my counting:
Of the numbers starting with 3:
C(11,1)=11 have a single 7
C(11,2)=55 have a pair of 8s
That got me from #13 to #78
Past #78 our reasoning looks identical.

Posted by Jer
on 20151009 08:16:30 