 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  sum of digits and 100th term (Posted on 2015-10-08) s(x) denotes the sum of digits of x.
Consider all the positive integer values of n satisfying s(n) = 100 arranged in strictly ascending order of magnitude.
Determine the 100th term of this sequence.

 No Solution Yet Submitted by K Sengupta No Rating Comments: ( Back to comment list | You must be logged in to post comments.) I did miss something in the previous post. Comment 3 of 3 | (In reply to I've probably miscounted but here goes. by Charlie)

```
total
count         so far
1, then 11 9's                                              1              12, then an 8 instead of one of the 9's                     11             123, then a 7 instead of one of the 9's                      11             233, then 8's replacing two of the 9's            C(11,2) =  55             7846, then 10 9's  (we're not getting to 49...)               1             7947, then an 8 and nine 9's                      C(10,1) =  10             89487, then nine 9's                                          1             90 48, then two 8's with 8 9's                     C(10,2) =  55       more than 100```
`It's among the last category`
`#91    488899999999#92    488989999999#93    488998999999#94    488999899999#95    488999989999#96    488999998999#97    488999999899#98    488999999989#99    488999999998#100   489889999999`

However, pondering this last one, which I previously gave as the answer, I see that 489799999999  (formatted 489,799,999,999) would be the next in line, as #100, and the categorization was flawed.

 Posted by Charlie on 2015-10-09 08:27:51 Please log in:

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