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 From E to D (Posted on 2015-04-28)
Easy
3 \$ 2 = 15
7 \$ 4 = 311
62 \$ 13 = 4975
51 \$ 43 = ???

Harder:
15 \$ 11 = 104
18 \$ 7 = 275
62 \$ 13 = 3675
24 \$ 1 = ???

Difficult:
31 \$ 41 = 592
27 \$ 18 = 281
16 \$ 180 = 339
33 \$ 21 = ???

A \$ B denotes a function of A and B, unchanged within a section.

 See The Solution Submitted by Ady TZIDON No Rating

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 Solution explained Comment 4 of 4 |

As this post has been for several months without solution I suppose nobody is working on it. So I explain the solution.

The first section is very easy (3 \$ 2 = 15) because (3-2 =1; 3+2 =5).

The second section is not difficult (15 \$ 11 = 104) because (15+11=26 and 15-11=4; 26*4=104)

The third section is simple but a posteriori. When you notice that 31 \$ 14 = 592 is derived from π = 3,141592.

31 \$ 41 = 592 is from π = 3,141592…

27 \$ 18 = 281 is from e = 2,718281… (Euler’s number)

16 \$ 180 = 339 is from φ = 1,6180339… (Golden’s number).

So, the solution for 33 \$ 21 = ? would be a number whose first digits are: 3,321… The best candidate to this I suppose is number x that  2^x=10 (logarithm of 10 in base 2).

x= 3,321928…  and then 33 \$ 21 = 928

***************************

When I was thinking on it I thought the question posted was 21 & 33 (instead of 33 &21).

I found a surprising and quite different solution for that.

Because 2,133… is 32/15 that could came from 3 \$ 2 = 15, just the first sequence of the first section.

In that case the title of the post would have been: From E to D and From D to E.

Edited on November 19, 2015, 9:22 am

Edited on November 19, 2015, 9:26 am
 Posted by armando on 2015-11-19 09:21:03

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