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On his way to fitness (Posted on 2015-06-15) Difficulty: 2 of 5
Johny, trying to reduce, followed a certain diet
during the month of April.
He recorded his weight daily at 8:00, naked, using the same balance.
Some of his entries are given below:

Apr 3...........102.6 kg
Apr 8...........101.1 kg
Apr 14.........99.4 kg
Apr 18.........98.7 kg
Apr 22.........98.0 kg
Apr 28..........97.6 kg

Please provide your estimate of his average April weight.

No Solution Yet Submitted by Ady TZIDON    
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re: A geometrical approach | Comment 4 of 10 |
(In reply to A geometrical approach by Jer)

I would think that regardless of what integration formula you use on the data given, that, say .5 kg be added to whatever average is arrived at.  8 AM would be the low weight for a given day, and the high point for the day could very well be 1 kg higher.  Regardless of the slope going up and then down again, the average would be higher by 1/2 this difference.

Why would be given the time of day if it were not of significance? If told merely that it was the same time every day, we'd still know we had to integrate over 30 days, rather than merely between April 1 and April 30 (only 29). The specific time tells us something.

  Posted by Charlie on 2015-06-15 14:45:15
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