Thanks to Ravi for introducing me to these with his problems but here goes.
A father, mother, son, daughter and grandmother are all compairing ages. They find out this:
1) When the mother was the daughter' current age, the grandmother was twice as old as the father.
2) In one year, the father will be twice as old as his son.
3) When the daughter was 2/3 her current age, the son was twice as old as she was.
4)When the mother was 10 years younger than the daughter will be when she is twice her current age, the grandmother was twice as old as the mother was.
What are all the ages in the family?
(In reply to my solution
In one year the father will be 41 and the son 21, so the father won't then be twice his son's age.
When the daughter is twice 12 she'll be 24. When the mother was 10 years younger than that, that is 14, was 20 years ago. At that time the grandmother was 38 and the mother 14, so the grandmother would have been more than twice as old as the mother was.
Posted by Charlie
on 2003-07-17 09:19:27