a. The digits of N! can be rearranged to form a prime.
b. N>2
Find the smallest N, complying with the above statements.
8! = 40320
put the '0's together to make an '8'
now you have the digits 4,3,2, and 8
Several primes can be formed from these 4 digits, all ending in 3:
2843
4283
8243
8423
So the requested smallest N is 8.

Posted by Larry
on 20200519 11:54:42 