Find a geometric series of 3 or more positive integers, starting with 1, such that its sum is a perfect square.
See if you can find another such series.
The sum of the first n terms of a geometric series is:
S_{n} = t_{1}(1r^n)/(1r)
where t
_{1} is the first term and r is the common ratio (and not 0).
Since this problem specifies that
t_{1}=1, we need to find a solution for
S_{n} = (1r^n)/(1r) = x²
where x, r, and n are all integers.
I haven't time to complete it now (back to work!), but that is where I think we need to start.

Posted by DJ
on 20030714 06:43:22 