An eleven digit duodecimal positive integer N is constituted by each of the nonzero digits from 1 to B exactly once, such that N satisfies all the following conditions.

• The sum of the digits 1 and 2 and all the digits between them is equal to the duodecimal number 12.

• The sum of the digits 2 and 3 and all the digits between them is equal to the duodecimal number 23.

• The sum of the digits 3 and 4 and all the digits between them is equal to the duodecimal number 34.

• The sum of the digits 4 and 5 and all the digits between them is equal to the duodecimal number 45.

• The sum of the digits 5 and 6 and all the digits between them is equal to the duodecimal number 56.

If the first digit of N is more than the last digit, determine all possible value(s) that N can assume.

Note: Think of this puzzle as an extension of An ID Number Problem.

Eight-Digit Numbers In Reverse | Rating: 2.50
Posted on 2009-06-28 by K Sengupta (No Solution Yet, 3 Comments)

Powering Up The Matrix |
Posted on 2009-06-20 by K Sengupta (No Solution Yet, 3 Comments)

2*s³ = 3*t² + 4 |
Posted on 2009-06-13 by K Sengupta (No Solution Yet, 3 Comments)

Tom and Harry Run to School |
Posted on 2009-05-20 by Charlie (Solution Posted, 2 Comments)

Exploring New Guinea (based on a true story!) | Rating: 4.00
Posted on 2009-05-07 by FrankM (Solution Posted, 2 Comments)

Factorials and Powers | Rating: 4.00
Posted on 2009-04-22 by K Sengupta (No Solution Yet, 8 Comments)

Way to minimum and maximum | Rating: 1.00
Posted on 2009-04-08 by K Sengupta (No Solution Yet, 4 Comments)