perplexus.info :: Sequences : Flawless Series?

Flawless Series? (Posted on 2003-11-29)

What are the next three numbers in this sequence? 6, 28, 496, 8128, ... ? Please explain how you determined these three numbers.

See The Solution Submitted by SilverKnight

Rating: 3.1000 (10 votes)

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Real Answer

| Comment 30 of 93 |

Obviously t(n) = (3359/3)n³ -6495n² +(35008/3)x-6288.

Posted by Hal9000 on 2003-11-30 16:37:32

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