5 Girls (named Alice, Betty, Carol, Diane, Emily) visit a mall to shop. They come upon a clothing shop and they decide to buy clothing.

But, for some strange reason, different colored shirts cost different amounts, which now came in increments of 10 dollars. (Every shirt of the same color costs the same amount.) This store doesn't carry very many shirts; the most expensive one is 50 dollars, and they only come in red, green, blue, yellow, and orange.

Each girl goes into the store and finds two different shirts. No two girls got the same pair of shirts, and no girl got a shirt for free. It ended up that each color shirt was bought exactly twice.

Using the following clues, can you figure out the two colors of shirts each girl bought, and how much each color bought, as well as how much each girl spent?

1) When the 5 girls were comparing their purchases, they found that Diane spent the most money, 2 girls tied for second most money spent, and the other 2 girls spent the same amount of money as well.

2) When Carol bought the blue shirt, she was mad that the it was more expensive than the 10-dollar price it was last week, and didn't buy the green shirt because of this.

3) Diane's and Emily's different styles resulted in them not buying any shirts the same color as each other's.

4) Alice and Emily both decided not to buy the orange shirt, but instead, Alice went with Carol to pick out the same color shirt to buy, noting that it didn't cost 20 dollars like last week.

5) As Betty was waiting to buy a red shirt (which she did end up buying), she saw Carol buy a shirt that cost 40 dollars.

I'm new at this, so you'll have to forgive me if I have posted things that people have already said. But since it is said to be as yet unsolved, here goes. (INHALE)
1) 50 is the most expensive, which leaves the other prices to be 10, 20, 30, 40. Diane spent the most. Possible pairs 50+40=90 and 50+30=80. 90 as a possible pair would mean that 3 girls would have to have bought 40 shirts. So Diane spent $80. The pairs left are 10+50 and 20+40 =60 and 10+40 and 20+30=40.
2)Emily and Diane didn't buy the same shirts[3], so Emily didn't spend either $30 or $50 on a shirt, so she spent $40 on one. Because Carol spent $40[5], we know she didn't spend 30 or $50. The shirt that Alice and Carol bought in common wasn't $20[4], so it was $10. So Alice also bought a $50 shirt, Emily a $20 shirt and Betty $20 and $30 shirts. That gives me:
Alice 10+50=60
Betty 20+30=50
Carol 10+40=50
Diane 30+50+80
Emily 20+40=60 okay....
3) Blue and Green are not $10 [2], and Carol bought a blue shirt[2], and spent $10 and $40 on shirts. Therefore, blue is $40. Emily bought a blue shirt. Carol didn't buy a green shirt [Green is not 10[2] and she bought a $10 shirt]. Betty bought a red shirt[5], and since Betty and Alice didn't spend the same amount on shirts, Alice didn't buy a red shirt. Alice and Emily didn't buy an orange shirt [4], which means Alice bought a yellow and green shirt. Since Green is not $10 [2], green is $50. So Diane bought a green shirt. And Yellow shirts are $10, so Carol bought a yellow shirt. Emily had to have bought a red shirt [since she didn't buy yellow nor green nor orange] Therefore Red shirts are $20 [only amount Emily and Betty have in common]. Leaving Orange shirts to be $30, and they were bought by Betty and Diane. Final Answer:
Alice==> Yellow (10) and Green (50)
Betty==> Red (20) and Orange (30)
Carol==> Blue (40) and Yellow (10)
Diane==> Green (50) and Orange (30)
Emily==> Blue (40) and Red (20)

Does that make any sense?

Posted by Cindy on 2004-01-07 23:21:39