If you have a truncated cone such that its upper base has a radius of a and the radius of its [larger] lower base is b, and a height h (between bases), how could you figure out its surface area using geometric reasoning?
general equation:
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Frustrum (= truncated cone):
Volume = 1/3 (pi)* h *( a^ 2 + b^ 2 + a*b )
Surface Area = Lateral Area + Area of Base 1 + Area of Base 2
LA = (pi)* hs * ( a+b )
hs = SQROOT [ (a-b) ^2 + h^ 2 ]
AB 1 = (pi)*a^2
AB 2 = (pi)*b^2
that replaces my previous entry
ady
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general equation:
