Find the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.

5-digit number:
ideally, it would be: (for number abcde)
1.5 (10000a + 1000b + 100c + 10d+ e) = 10000e + 1000a + 100b + 10c + d
15000a + 1500b + 150c + 15d + 1.5e = 10000e + 1000a + 100b + 10c + d
14000a + 1400b + 140c + 14d = 9998.5e
14 (1000a + 100b + 10C + d) = 9998.5e
Like before, e must be even 2,4,6, or 8.
9998.5 x 2= 19997 REJECT not divisible by 14
9998.5 x 4= 39994 REJECT not divisible by 14
9998.5 x 6= 59991 REJECT not divisible by 14
9998.5 x 8= 79988 REJECT not divisible by 14
GAH, it is not a 5 digit number

to be continued
Edited on January 25, 2004, 2:11 pm

Posted by Victor Zapana on 2004-01-25 13:56:22