Find the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.

(In reply to ramblings 4 by Victor Zapana)

(this shud be read last, after u read all the other "ramblings...," or at least ramblings 4.)
its a 6-digit number: abcde4

10000a + 1000b + 100c + 10d + e = 28571
a = 2
b = 8
c = 5
d = 7
e = 1
So, the number is 285714.

Also, just from my thoughts, I think it can't be 0, coz it says "precisely 50%," and 0 can be 1.983% of 0, 2.124% of 0, 3% of 0, etc. and not only be 50%

Edited on January 25, 2004, 2:09 pm
Edited on January 25, 2004, 2:12 pm

Posted by Victor Zapana on 2004-01-25 14:05:01