Find sum of digits of:(1999)^1999.
[The final answer should be a single digit number, for example, (2)^16 = 65536 and the sum of its digits will be given by (6 + 5 + 5 + 3 + 6 = 25, which again will be reduced to 2 + 5 = 7].

(In reply to super easy by Ady TZIDON)

Ady,

I don't follow your logic...

1999 is congruent to 1 mod 9, but why does that mean that the 'sum of digits' of (1999)^1999 should be one?

- SK

Posted by SilverKnight on 2004-01-27 09:01:48