4 people play a game of chance. They each take turns until everyone has taken a turn, then they begin a new round. They stay in the same order every round. Every time a player takes a turn, they have a certain chance of winning. When someone wins, the game ends. They all have even odds of winning a game. The chance of someone winning in any given round is 3/5.
What is the probability for each person to win during their turns?
(In reply to
my solution by Ady TZIDON)
Ady, you wrote:
"CLEARLY:
pa=x
pb=x*( 1-x)
pc=x*( 1-x)*(1-pb)
pd=x*( 1-x)*(1-pb)*(1-pc)
and pa+pb+pc+pd=3/5"
this is not the case (well the last line anyway...)
It should read:
(1-pa)(1-pb)(1-pc)(1-pd) = (1 - 3/5)
re: my solution
