4 people play a game of chance. They each take turns until everyone has taken a turn, then they begin a new round. They stay in the same order every round. Every time a player takes a turn, they have a certain chance of winning. When someone wins, the game ends. They all have even odds of winning a game. The chance of someone winning in any given round is 3/5.

What is the probability for each person to win during their turns?

both of us interpret differently the statement "They all have even odds of winning a game. "
It is my understanding that the rules of the game imply a certain well-defined probability figure
x (=pa) for a single history-independent (=memory-less) event.
A valid example of such a game ( e.g. for x=2 0%)//rem: I CORRECTED THE ERRONEOUS NUMBERS WRITTEN PREVIOUSLY// is drawing one marble out of bag with 1 red and 4, black marbles and counting a draw of a red as a "win", IF BLACK THE MARBLE IS RETURNED INTO THE BAG AND THE GAME CONTINUES.

Also the numbers qualifying as an answer to the "game of luck" should add up to 100%-
which they do in my case and do not in yours.

Will appreciate your (or other members) comments

ady
Edited on January 31, 2004, 6:18 pm

Posted by Ady TZIDON on 2004-01-31 10:37:38