4 people play a game of chance. They each take turns until everyone has taken a turn, then they begin a new round. They stay in the same order every round. Every time a player takes a turn, they have a certain chance of winning. When someone wins, the game ends. They all have even odds of winning a game. The chance of someone winning in any given round is 3/5.
What is the probability for each person to win during their turns?
(In reply to
re(3): another remark to SK 'S solution by Ady TZIDON)
"I believe that further correspondance is really counter-productive, since both of us define different games."
As noted, my initial post assumed the same game you are talking about. I later modified it to treat the whole event as the single game.
"Your remark about inserting x instead of pb and pc is a valuable one and I am going to correct my answers accordingly -later. "
Hopefully, when you do the math, you will see that what you call x is 1 minus the fourth root of 2/5.
"It would be beneficial for everybody if the author (Tristian) will specify the nature of the game e.g. in terms of marbles in a bag. As you know in my model one draws a marble( the same distribution for everybody)- if won the game ends,- if not the marble is returned. "
Two problems here: (1) Tristan's idea was that the puzzle was to find the nature of the game given the specifications. (2) In this case marbles in a bag wouldn't work for the idea of the game as you see it, and as I originally saw it: the odds are irrational. As it turns out, in the other interpretation, the odds are rational, and can be expressed as I stated in a previous post, in terms of marbles in a bag.
Perhaps Tristan was infelicitous in specifying "Every time a player takes a turn, they have a certain chance of winning," making it sound as if each turn by each player had the same probability of a win. What apparently was meant was that "Every time a given player takes a turn, he or she has a certain chance of winning."
"I do not know how to pass my remarks to the author of the puzzle- may be you do. "
I'm sure Tristan will be logging on to see these comments.
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Posted by Charlie
on 2004-01-31 14:09:22 |