I think everyone (should) agree that if S is the solution, then S©÷-2=S. The problem here is that there are extraneous solutions.
Of course, S can't be negative, and the negative solution must account for negative square roots. There is another extraneous root though. ¡Ä©÷-2=¡Ä, at least as far as I know. I don't believe in this answer of course, but is my belief only enough proof? I can think of ways to prove it beyond reasonable doubt, but not truly prove it, if you know what I mean.
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Posted by Tristan
on 2004-02-20 17:25:04 |