Four pairs of lords and ladies all went to a royal ball. Each lord was wearing one color (yellow, red, blue, or green) and each lady was also wearing one of these colors. No couple was wearing the same color, so it was hard to tell who was married to who.

Using the clues, can you determine which lord is with which lady?

1. The Green Lord is with the Red Lady, if and only if the Yellow Lord is with the Blue Lady.

2. The Yellow Lord is with the Red Lady if and only if the Green Lord is with the Yellow Lady

3. The Red Lord is with the Blue Lady, if and only if the Green Lord is with the Red Lady.

(In reply to possible solution maybe....kinda? :s by zeine)

Nah.. the solution is dead on. I read all the other "Possible solutions" and they won't work. Lemme tell you why.

Firstly, it says the Green => Red IF AND ONLY IF Yellow => Blue. The third clue says that Red => Blue IF AND ONLY IF Green => Red.

Hold up.

If (Clue 3) Red => Blue then Green => Red and if (Clue 1) Green => Red, then Yellow => Blue. But Yellow ≠ Blue. Red => Blue, as per Clue 3. Therefore, what can we infer? You can infer this: Green is not with Red. Yellow is not with Blue. Red is not with Blue.

Right there, we see that the Blue lady is getting kinda lonely. She's not with Red, or Yellow. We know she's not with the Blue stud, because the multi colorness started this whole problem. She can therefore be with only one other person. That's how you solve it. You don't assume that all the clues are false ;-). Oh well. He was smarter than I. He got the solution the fastest, and in the end, isn't that what matters?

-TenLetters

Posted by Ten on 2004-04-26 04:22:54