A "Pythagorean Plus One" triple can be defined as any three distinct integers a, b, c, such all three of these are one more than a perfect square, and also a times b equals c.
What is the lowest value of c possible?
(In reply to
solution by Gururaj)
Yes, (x^2+1)((x+1)^2+1)=(x^2+x+1)^2+1, something of a surprise! Thanks.
Edited on May 23, 2004, 7:04 pm
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Posted by Richard
on 2004-05-22 21:24:38 |
re: solution
