Find a 3x3 magic square composed of distinct proper fractions with no denominator greater than 9.

Note: A proper fraction is a fraction between 0 and 1. A proper fraction is NOT equal to 0 or 1.

Am I missing something?

It seems one could take any integer magic square and divide all the terms by a constant.

Example:

6  7  2

1  5  9

8  3  4

divided by 11 becomes

6/11  7/11  2/11

1/11  5/11  9/11

8/11  3/11  4/11

A more challenging alternative might be all having different denominators when in lowest terms.  Also smallest maximum denominator.

-Jer 

Posted by Jer on 2004-05-24 09:13:13