Place nine different digits (from 0-9) into a 3x3 grid, such that the eight sums formed by the three rows, three columns and two diagonals are consecutive numbers.

(In reply to re(3): Question by Juan)

What I ended up doing is making it so that all three rows and the diagnals added up to the same number: 14.

Rows:

1 + 6 + 7 = 14

0 + 5 + 9 = 14

2 + 4 + 8 = 14

Diagnals:

1 + 5 + 8 = 14

2 + 5 + 7 = 14

 

Posted by Juan on 2004-06-23 14:20:20