Place nine different digits (from 0-9) into a 3x3 grid, such that the eight sums formed by the three rows, three columns and two diagonals are consecutive numbers.

(In reply to re(4): Question by Juan)

Okay, here it is- Again, but this time it works.

Rows:

6 + 7 + 1 = 14

5 + 8 + 2 = 15

4 + 9 + 3 = 16

Diags:

4 + 8 + 1 = 13

6 + 8 + 3 = 17

 

Posted by Juan on 2004-06-23 14:48:36