Look at this shape:

Assume AB = AF = FE = ED and BC = CD, and all the angles in the shape are 90 degrees.

Let A be the area of this shape (in cm^2), and P -- the perimeter of this shape (in cm).

If A - P is 60, what is the length of line AC?

AB=l, Area= (4l^2)-l^2=3l^2

perimeter=8l

equation:3l^2-8l-60=0

l=[8+(784)^0,5]/6

l=[8-(784)^0,5]/6(not real)

Posted by vije on 2004-07-07 13:42:35