There is a point M inside a square ABCD such that angle MAB is 60° and angle MCD is 15°. Find angle MBC.
MBC=45º, because if you unite(AM) to (DC) yo get a point H, unite (BM) to (DC) you get a point N, ΔAMB~ΔMNH(<M=<M=75º; <H=<A=60º) and MBC=90-ABM=90-45=45.
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Posted by vije
on 2004-07-14 05:01:38 |