There is a point M inside a square ABCD such that angle MAB is 60° and angle MCD is 15°. Find angle MBC.
The square sides are paralel (in this case), the side of the angle MCD is like a paralel but rotated at 15grd, CMB is an angle equal to 105-n(n is MBC) and it is equal to MAB+CMB=75 => n=105-75=30
MCB=75 =90-MCD CMB=180-n-75=105-n
Elegant no?
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Posted by vije
on 2004-07-20 05:41:40 |
A new aproach
