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10,000 (Posted on 2004-07-21) Difficulty: 3 of 5
Find all series of consecutive positive integers whose sum is exactly 10,000.
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What if we don't require the consecutive integers to (all) be positive?

See The Solution Submitted by SilverKnight    
Rating: 3.0000 (5 votes)

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Solution | Comment 3 of 10 |

First, we can see that some of the solutions require integral multiples of 10000. For example, 2000 divides 10000 5 times, so there are 5 terms: 2000, two above, and two below. Similarly, we can determine more sequences.

For negative terms, notice the symmetry about zero. Thus, for each positive term N starting a sequence, there is a sequence starting at (-(N-1)). The endpoints are the same. The sequences are:

{-9999,10000} to 10000

{-1997,1998} to 2002

{-387,388} to 412

{-296,297} to 328

{-17,18} to 142

 

 

 

 


  Posted by Eric on 2004-07-21 09:34:05
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