All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Jack's Ladder (Posted on 2004-07-27) Difficulty: 2 of 5
Even though it was now middle of winter, Jack hauled out his ladder and placed his ladder against the side of the house and began to climb. He had some bad luck when he reached the half-way point. The ground was a frozen sheet of ice and the base of his ladder slipped out and the top slid down the side of the house. Jack, clinging to the center rung, wound up moving from Point A on the side of his house to Point B on the ground.

Describe the path Jack traveled.

See The Solution Submitted by Brian Smith    
Rating: 2.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution Via Coordinates | Comment 10 of 23 |

If the ladder is 1 unit long then at any point of its slide it looks like

                      |
                      |
(0,sqrt(1-x^2))|\
                      |  \
                      |    \
                      |      \
                      |        \
                      |______\____
                    (0,0)    (X,0)

The midpoint of the ladder has coordinates (x,y)=(X/2,(sqrt(1-X^2))/2) which satisfy x^2+y^2=1/4.  The midpoint of the ladder is thus on a circle with radius 1/2 centered at the origin.


  Posted by Richard on 2004-07-27 15:00:39
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information