(i) A has at least one girl and twice as many boys as girls.

(ii) B has at least one girl and three times as many boys as girls.

(iii) C has at least one girl and three more boys than girls.

(iv) When I tell you the number of children we have – a number less than 25 – you will know how many children I have, but not how many children each of the others has. Altogether we have……..”

Who is the speaker and how many children does the speaker have?

A = 3,6,9,12,15

B = 4,8,12,16

C = 4,5,6,7,8,9,10,11,12,13,14,15,16,17

it cant be 11,12 or 13 because we would know how many children each person has.

Possible solutions:

14 xx

15 xxx

16 xxx

17 xxxx

18 xxxxx

19 xxxxxxx

20 xxxxxxx

21 xxxxxxx

22 xxxxxxxxx

23 xxxxxxxxxxx

24 xxxxxxxxxxx