Triangle ABC is isosceles with AB=BC. There is a point D on AC such that BD = DC and AB=AD.

What is the measure of angle BAC?

(In reply to re: Solution + Explanation by Charlie)

For Charlie:

I could follow your explanation till i reached this:

"Actually, where did AB = AD come from?  By symmetry, since BD = DC, it is BD = AD.  And since angle ABD equals angle a, and angle CBD = angle a, and they add up to angle ABC, b=2a. But b+2a = 180 degrees. So b = 90 degrees and a = 45 degrees."

Why are you taking BD=AD, when the question says it is AB = AD ???

Edited on September 1, 2004, 9:32 am

Posted by Syzygy on 2004-09-01 09:31:15