Triangle ABC is isosceles with AB=BC. There is a point D on AC such that BD = DC and AB=AD.
What is the measure of angle BAC?
(In reply to
re: Solution + Explanation by Charlie)
<<Actually, where did AB = AD come from? By symmetry, since BD = DC, it is BD = AD. And since angle ABD equals angle a, and angle CBD = angle a, and they add up to angle ABC, b=2a. But b+2a = 180 degrees. So b = 90 degrees and a = 45 degrees.>>
AB = AD was given
How did you get BD = AD? Triangles ABC and BDC are similar, not congruent, right?
I'm very confused.
|
|
Posted by nikki
on 2004-09-01 09:34:43 |
re(2): Solution + Explanation
