All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Numbers
Another last digit (
Posted on 2004-09-07
)
What's the last digit of 11^2003 times 7^2004 times 13^2005 ?
See The Solution
Submitted by
Federico Kereki
Rating:
2.5000
(4 votes)
Comments: (
Back to comment list
| You must be logged in to post comments.
)
Simpler solution
| Comment 2 of 10 |
11^2003x7^2004x13^2005 = (11x7x13)^2003x7x13^2 = 1001^2003x7x169. The last digit of 1001^2003 is 1, so the last digit of the whole product is 3, the last digit os 7x169.
Posted by
Oskar
on 2004-09-07 07:01:06
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information