All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Another last digit (Posted on 2004-09-07) Difficulty: 1 of 5
What's the last digit of 11^2003 times 7^2004 times 13^2005 ?

See The Solution Submitted by Federico Kereki    
Rating: 2.5000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Simpler or not? | Comment 5 of 10 |

The easiest solution I see is to notice that every odd number to an exponent divisible by 4 will end in 1, because every 4 terms must repeat, and since any number to the 0 ends in 1, such must the others. So then it's just 7 * 9 ends in 3.

I think we all have different definitions of simplest :)


  Posted by Gamer on 2004-09-07 17:02:46
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information