![](http://perplexus.info/images/perplexus/problem/mta3-puz.gif)
Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
I made this diagram using geometer's sketchpad
It didn't yield any insights that led me to a proof, but I did find the angle.
It is 70 degrees.
-Jer
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Posted by Jer
on 2004-09-08 12:40:50 |