![](http://perplexus.info/images/perplexus/problem/mta3-puz.gif)
Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
(In reply to
re: Solution by cheating by Brian Smith)
Wait a minute... Am I missing something?
You picked E so that AD=DE. And we know that AD = BC. But how do you know DE=EB?