Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
(In reply to
re: first part by Jim)
In your third line you say "The angles about point F are 60 and 120."
I don't understand how you got that. I agree that it is true, but I don't see how you found it to be true. Could you explain?
Also, it was a little confusing at first trying to visualize your triangle ADE. I wasn't sure where E should be (up-left or down-right of segment AD). Based on your other comments, it seems like E should be up-left, so I think I followed you correctly.
Thanks!
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Posted by nikki
on 2004-09-09 17:11:54 |
re(2): first part
