A six-shooter is loaded with three cartridges
in consecutive chambers, before two persons start to play "Russian Roulette" until one is dead.
If the cylinder isn't spun after each attempt, would you rather be the first shooter, or the second?
What would be your answer if there are only TWO cartridges, of course in consecutive chambers?
(In reply to
Duck Duck Goose! by Celie)
Therefore, the possible combinations are:
bbbeee
ebbbee
eebbbe
eeebbb
beeebb
bbeeeb
If you take the first shot, you will die on the sequences bbbeee, eebbbe, beeebb, and bbeeeb. You thus want to go second.
In the latter case, the possible combinations are:
bbeeee
ebbeee
eebbee
eeebbe
eeeebb
beeeeb
Here the first shooter dies on bbeeee, eebbee, eeeebb, and beeeeb. So you want to go second.