A six-shooter is loaded with three cartridges
in consecutive chambers, before two persons start to play "Russian Roulette" until one is dead.
If the cylinder isn't spun after each attempt, would you rather be the first shooter, or the second?
What would be your answer if there are only TWO cartridges, of course in consecutive chambers?
In both cases I should go first. The odds go down significantly with every shot. This is quite clear using very little math or formula(or should I say formuli(is that really a word?)). The first shooter has either a 1/2 or (2nd case) a 1/3 chance of blowing her/his brains out. The second has person will be left with either a 3/5 or (2nd case) 2/5.
After that I don't see the point. Once I have decided to to first, the rest is dictated.
But If I was going up against Federico, I would go second. My simple logic would be that he proposed this question to trick me into going first.
almost not math
