Take the digits
2, 0, 0 and 3. Make equations equating to all the integers from 1 to 150 using these digits according to the following rules:-
a) The above digits are the only digits to be used and no other digits should appear anywhere in the equation (except on the side where the answer will be).
b) Use of any mathematical symbols are allowed.
c) The digits 2, 0, 0 and 3 should appear in the given order in the equation. e.g - 0 + 2 + 3 + 0 = 5 is not acceptable.
d) When using the mathematical symbols try using the most simplest forms as much as possible.
I've found another useful function: I don't remember what it's called, and can't quite draw it here, but it's the combinatorics notation for 'choosing x objects out of y', and is written in brackets (), with y on top and x on the bottom.
The formula for x out of y is: y! / (x! * (y-x)!)
Thus we have:
[(2+0!)! + 0!] over 3, which gives us 3 out of 7, or 7! / (3!*4!) = 35.
Haven't found any others yet with this function...
interesting 35
