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Summing Squares Sequentially! (Posted on 2004-10-01) Difficulty: 3 of 5
Show that if you sum 9999 consecutive squares, the result cannot be a perfect power.

See The Solution Submitted by Old Original Oskar!    
Rating: 2.0000 (2 votes)

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re(2): Solution (slight correction) | Comment 4 of 10 |
(In reply to re: Solution by Federico Kereki)

Instead of saying that the roots should be 33 and 101, I should've said that when you multiply the two roots, the answer should be a multiple of 3333 in order for the sum to be a perfect power.

But that doesn't change the answer.


  Posted by np_rt on 2004-10-01 15:35:04
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