Show that if you sum 9999 consecutive squares, the result cannot be a perfect power.
(In reply to
re: Solution by Federico Kereki)
Instead of saying that the roots should be 33 and 101, I should've said that when you multiply the two roots, the answer should be a multiple of 3333 in order for the sum to be a perfect power.
But that doesn't change the answer.
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Posted by np_rt
on 2004-10-01 15:35:04 |